%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SET062^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:45:23 EDT 2023

% Result   : Theorem 3.38s 3.55s
% Output   : Proof 3.38s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SET062^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n010.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 10:19:50 EDT 2023
% 0.21/0.35  % CPUTime    : 
% 3.38/3.55  SZS status Theorem for theBenchmark.p
% 3.38/3.55  SZS output start Proof for theBenchmark.p
% 3.38/3.55  Clause #0 (by assumption #[]): Eq (Not (∀ (X : a → Prop) (Xx : a), False → X Xx)) True
% 3.38/3.55  Clause #1 (by clausification #[0]): Eq (∀ (X : a → Prop) (Xx : a), False → X Xx) False
% 3.38/3.55  Clause #2 (by clausification #[1]): ∀ (a_1 : a → Prop), Eq (Not (∀ (Xx : a), False → skS.0 0 a_1 Xx)) True
% 3.38/3.55  Clause #3 (by clausification #[2]): ∀ (a_1 : a → Prop), Eq (∀ (Xx : a), False → skS.0 0 a_1 Xx) False
% 3.38/3.55  Clause #4 (by clausification #[3]): ∀ (a_1 : a → Prop) (a_2 : a), Eq (Not (False → skS.0 0 a_1 (skS.0 1 a_1 a_2))) True
% 3.38/3.55  Clause #5 (by clausification #[4]): ∀ (a_1 : a → Prop) (a_2 : a), Eq (False → skS.0 0 a_1 (skS.0 1 a_1 a_2)) False
% 3.38/3.55  Clause #6 (by clausification #[5]): Eq False True
% 3.38/3.55  Clause #8 (by clausification #[6]): False
% 3.38/3.55  SZS output end Proof for theBenchmark.p
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